3x^2+7x=300

Solution for 3x^2+7x=300 equation:

3x^2+7x=300

We move all terms to the left:

3x^2+7x-(300)=0

a = 3; b = 7; c = -300;
Δ = b2-4ac
Δ = 72-4·3·(-300)
Δ = 3649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{3649}}{2*3}=\frac{-7-\sqrt{3649}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{3649}}{2*3}=\frac{-7+\sqrt{3649}}{6}
$